How do you divide # (6-10i) / (7-2i) #?
1 Answer
Dec 18, 2015
Multiply both numerator and denominator by the Complex conjugate of the denominator and simplify to find:
#(6-10i)/(7-2i) =62/53-58/53i#
Explanation:
#(6-10i)/(7-2i)#
#=((6-10i)(7+2i))/((7-2i)(7+2i))#
#=((6)(7)+(6)(2i)+(-10i)(7)+(-10i)(2i))/(7^2+2^2)#
#=(42+12i-70i+20)/(49+4)#
#=(62-58i)/53#
#=62/53-58/53i#
