How do you factor the expression #(x+3)^2 - 4#?
1 Answer
Dec 20, 2015
Use difference of squares identity to find:
#(x+3)^2-4=(x+1)(x+5)#
Explanation:
The difference of squares identity can be written:
#a^2-b^2=(a-b)(a+b)#
Use this with
#(x+3)^2-4#
#=(x+3)^2-2^2#
#=((x+3)-2)((x+3)+2)#
#=(x+1)(x+5)#
