What is the vertex of y=-3x^2-4x+2(x-2)^2 ?

1 Answer
Dec 23, 2015

(4,24)

Explanation:

Simplify first
y= -3x^2-4x+2(x-2)^2
y= -3x^2 -4x + 2(x^2+4x+4)
y= -3x^2 -4x + 2x^2 +8x+8
y= -x^2 +8x+8

Now to solve for the vertex algebraically , we use the formula
Vertex= ( -b/(2a) , f(-b/(2a) ) )
-b/(2a) = 4
f(4)= 24

Vertex = (4,24)