How do you solve #ln(3x)=8.2#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Özgür Özer Dec 23, 2015 #color(white)(xx)x=e^(8.2-ln3)# Explanation: #color(white)(xx)ln(3x)=8.2# #=>ln3+lnx=8.2# #=>ln3+lnx-color(red)ln3=8.2-color(red)ln3# #=>x=e^(8.2-ln3)# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 3712 views around the world You can reuse this answer Creative Commons License