How do you find $f (g (4))$ $f(g(4))$ if $f (x) = 2 \sqrt{x + 3}$ $f(x)=2sqrt(x+3)$ and $g (x) = - 3 x + 1$ $g(x)=-3x+1$ ?

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How do you find $f (g (4))$ $f(g(4))$ if $f (x) = 2 \sqrt{x + 3}$ $f(x)=2sqrt(x+3)$ and $g (x) = - 3 x + 1$ $g(x)=-3x+1$ ?

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Answer 1 · 2015-12-24T06:29:44

$f (g (4)) = 4 i \sqrt{2}$ $f(g(4))=4isqrt2$

Explanation:

First, find $g (4)$ $g(4)$ . Then, plug that value into $f (x)$ $f(x)$ .

Find $g (4)$ $g(4)$ :

$\times \times \times x g (4) = - 3 (4) + 1$ $color(white)(xxxxxxx)g(4)=-3(4)+1$
$\times \times \times x g (4) = - 11$ $color(white)(xxxxxxx)g(4)=-11$

Find $f (g (4))$ $f(g(4))$ , which is equivalent to $f (- 11)$ $f(-11)$ :

$\times \times \times x f (- 11) = 2 \sqrt{- 11 + 3}$ $color(white)(xxxxxxx)f(-11)=2sqrt(-11+3)$
$\times \times \times x f (- 11) = 2 \sqrt{- 8}$ $color(white)(xxxxxxx)f(-11)=2sqrt(-8)$
$\times \times \times x f (- 11) = 2 \cdot 2 i \sqrt{2}$ $color(white)(xxxxxxx)f(-11)=2*2isqrt(2)$
$\times \times \times x f (- 11) = 4 i \sqrt{2}$ $color(white)(xxxxxxx)f(-11)=4isqrt2$

Thus,

$\times \times \times x f (g (4)) = 4 i \sqrt{2}$ $color(white)(xxxxxxx)f(g(4))=4isqrt2$

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How do you find $f (g (4))$ $f(g(4))$ if $f (x) = 2 \sqrt{x + 3}$ $f(x)=2sqrt(x+3)$ and $g (x) = - 3 x + 1$ $g(x)=-3x+1$ ?

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How do you find f(g(4))f(g(4))f(g(4)) if f(x)=2sqrt(x+3)f(x)=2√x+3f(x)=2sqrt(x+3) and g(x)=-3x+1g(x)=−3x+1g(x)=-3x+1?

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How do you find $f (g (4))$ $f(g(4))$ if $f (x) = 2 \sqrt{x + 3}$ $f(x)=2sqrt(x+3)$ and $g (x) = - 3 x + 1$ $g(x)=-3x+1$ ?