What is the standard form of y=(2x-7)(-x+2) -5x^2-8?

1 Answer
Dec 25, 2015

y = -7x^2 +11x -22

Explanation:

To write this in standard form, we need to

1) Multiply/Expand the fist two factor

2) Then combine like terms

y = (2x-7)(-x+2) -5x^2 -8

=> (-2x^2 +4x +7x -14) -5x^2 -8
=> -2x^2 +11x -14 -5x^2 -8
=>y = -7x^2 +11x -22