What is the derivative of #y= tan^-1(x^2)#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer Konstantinos Michailidis Dec 26, 2015 The derivative of #arctanf(x)# is #d(arctanf(x))/dx=(f'(x))/(1+(f(x))^2)# where #f(x)=x^2# hence #d(arctanx^2)/dx=(2x)/(1+(x^4))# Answer link Related questions What is the derivative of #y=cos(x)# ? What is the derivative of #y=tan(x)# ? How do you find the 108th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x)# from first principle? How do you find the derivative of #y=cos(x^2)# ? How do you find the derivative of #y=e^x cos(x)# ? How do you find the derivative of #y=x^cos(x)#? How do you find the second derivative of #y=cos(x^2)# ? How do you find the 50th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x^2)# ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 3096 views around the world You can reuse this answer Creative Commons License