How do you solve log(x) + log(2x + 1) = 1log(x)+log(2x+1)=1?

1 Answer
Dec 27, 2015

color(white)xxx_1=2×x1=2
color(white)xxx_2=-5/2×x2=52

Explanation:

color(white)xxlogx+log(2x+1)=1×logx+log(2x+1)=1

=>logx(2x+1)=1logx(2x+1)=1
=>2x^2+x=102x2+x=10
=>2x^2+x-10=02x2+x10=0

color(white)xxDelta=81
=>x_(1,2)=(-1+-9)/4

=>x_1=2
=>x_2=-5/2