Question

The second term of a geometric sequence is 6 and the fifth term is -48. How do you find the tenth term of the sequence?

Answer 1

First find the common ratio `r` ...

Explanation:

`-48/6 =r^[(5-2)]`

`r=(-48/6)^(1/3)=-2`

Tenth Term `=(-48)(-2)^5=1536`

Hope that helped