How do you find the vertex of #y=2x^2 +11x-6#?

1 Answer
Dec 29, 2015

So, the solution set - or vertex set - is #(-11/4,-169/8)#

Explanation:

The x of the vertex(#x-vertex#) is found using the formula:
#"x-vertex" = -b /(2a) #, in this case: # "x-vertex" = -11/4#.
The y of the vertex(#y-vertex#) is found using the formula:
#"y-vertex" = - triangle/(4a) = - (b^2 -4ac) / (4a)#, in this case: #"y-vertex" = - [121 - (4 " x " 2" x"-6)] / (4 " x "2) =- 169/8 #.
So, the solution set - or vertex set - is #(-11/4,-169/8)#