Question

What is the vertex form of #y=-2x^2+17x+13 ?

Answer 1

The co-ordinate of vertex is `(4.25,49.125)`

Explanation:

The general form of Parabola is `y=a*x^2+b*x+c`
So here `a=-2 ; b=17 ; c=13`
We know the x co-ordinate of the vertex is `(-b/2a)`
Therefore the x co-ordinate of the vertex is `(-17/-4)` or `4.25`
Since the parabola passes through vertex the y co-ordinate will satisfy the above equation. Now putting `x=17/4` the equation becomes `y=-2*17^2/4^2+17*17/4+13` or `y =49.125`
Thus the co-ordinate of vertex is `(4.25,49.125)`[answer]