How do you solve log_7 12 = x?

1 Answer
Dec 29, 2015

From log definition, we have that log_ba=c <=>b^c=a

Explanation:

Thus,

log_7(12)=x <=> 7^x=12

Now, we can apply log on both sides of the equation.

log7^x=log12

Another log rule states that log_ba^n=n*log_ba, so:

x*log7=log12
x=log12/log7 (both on base 10 or base e or whatever base you end up finding convenient! It really does not matter!)

Using a calculator, as these are not exact expressions, you can find the approximate value of

x~=1.277