A projectile is shot at an angle of pi/12 and a velocity of 46 m/s. How far away will the projectile land?

1 Answer
Dec 29, 2015

The projectile will fall 107.8m far

Explanation:

Consider the two equation of speed
s(x)=vt with v=cos15°
s(y)=vt-1/2at^2 with v=sin15°
Find the time when s(y)=0, so t(v-1/2at)=0
t(fall)=2v/g=2.43s and use this value in the horizontal equation
s(t)=(46cos15°)*2.43=107.8m