An object with a mass of 6 kg is traveling in a circular path of a radius of 1m. If the object's angular velocity changes from 6 Hz to 7 Hz in 3 s, what torque was applied to the object?

1 Answer

\tau = 12.562 N\cdotm

Explanation:

First, convert the given angular velocities to (rad)/s where 1Hz = (2\pi)(rad)/s
Therefore,
6Hz = 37.699 (rad)/(s)
7Hz = 43.98 (rad)/(s)

Torque is
\tau=Fl = mal

Finding for the tangential acceleration, use
v=v_0+at
where a = 2.09367 m/s^2

Therefore,
\tau = (6 kg)\cdot(2.09367 m/s^2)\cdot(1 m)
\tau = 12.562 N\cdotm