Question

An object with a mass of `6 kg` is traveling in a circular path of a radius of `1m`. If the object's angular velocity changes from `6 Hz` to `7 Hz` in `3 s`, what torque was applied to the object?

Answer 1

`\tau = 12.562 N\cdotm`

Explanation:

First, convert the given angular velocities to `(rad)/s` where `1Hz = (2\pi)(rad)/s`
Therefore,
`6Hz = 37.699 (rad)/(s)`
`7Hz = 43.98 (rad)/(s)`

Torque is
`\tau=Fl = mal`

Finding for the tangential acceleration, use
`v=v_0+at`
where `a = 2.09367 m/s^2`

Therefore,
`\tau = (6 kg)\cdot(2.09367 m/s^2)\cdot(1 m)`
`\tau = 12.562 N\cdotm`