Question

If a projectile is shot at a velocity of `17 m/s` and an angle of `pi/4`, how far will the projectile travel before landing?

Answer 1

The projectile travels `29.45m`

Explanation:

Consider the vertical equation `s(y)=vt-1/2at^2` and assume it equal to 0.
`s(y)=t(v-1/2at)=0` so `t=2v/g=2vsin45/g=2.45s`
Use this value in the horizontal equation `s(x)=vt=vcos45*t=vcos45*2.45=29.45m`