What is the value of #3xsqrt(8x) - 4sqrt(x^3) + 3xsqrt(72x)# when #x = 2#?

2 Answers
Jan 1, 2016

#96 - 8 √2 ≈ 84.7# ( #1# decimal place)

Explanation:

Substitute #x =2# into expression:
=6√16 - 4√8 + 6√144
=24 - 8√2 + 72
= 96 - 8√2

Jan 1, 2016

#color(brown)("As an approximate decimal value this is "84.69" to 2 decimal places.")#

#color(green)("To an EXACT value this is "=>96 - 8 sqrt(2))#

Hopefully my logic has not gone wrong!

Explanation:

Not taking any shortcuts so you can see what is happening.

Given: #3xsqrt(8x) - 4 sqrt(x^3)+3xsqrt(72x)color(white)(..) # ...... (1)

We may choose two approaches.

#color(blue)("Approach 1")#

Just do a strait substitution and calculate. This will most likely yield an imprecise decimal solution. Note they say "what is the value". Not "what is the approximate value".

#color(blue)("Approach 2")#

Simplify and stick with surds so that any answer is guaranteed to be precise.

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Adopting approach 2")#
Looking for factors that can be used to simplify:

Notice that #9xx8 =72# so we have a similarity within the expression of #8x#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(brown)("Consider: "-4sqrt(x^3) )# If you take the 4 inside the root you have to square it.

Write as : # -sqrt(16x xx x^2)=-sqrt(8x xx 2x^2)#

#-=-(xsqrt(2) xx sqrt(8x))#........................(2)

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(brown)("Consider: "+3xsqrt(72x) )#

Write as: #+3x sqrt(9 xx8x) -= +9xsqrt(8x)#......(3)
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Substitute (2 ) and (3 ) into (1 ) giving:")#

#3xsqrt(8x) -(xsqrt(2) xx sqrt(8x))+9xsqrt(8x)#........(4)

#color(brown)("Factoring out the "sqrt(8x))#

#sqrt(8x)color(white)(.)( 3x - sqrt(2 )color(white)(.)x+9x)#

#sqrt(8x)color(white)(.)( 12x - sqrt(2 )color(white)(.)x)#

#color(brown)("Factoring out the "x " from the btackets")#

#xsqrt(8x)(12-sqrt(2))#.........................(5)
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Substitute "x=2 " in (5 )")#

#(2)(sqrt(16))(12-sqrt(2))#

#8(12-sqrt(2))#

#=>96 - 8 sqrt(2)#

#color(brown)("As an approximate decimal value this is "84.69" to 2 decimal places.")#

#color(green)("To an EXACT value this is "=>96 - 8 sqrt(2))#