How do you find the vertex of # y=2x^2-4x-2#?

1 Answer
Binayaka C.
Jan 2, 2016

Co-Ordinate of Vertex is (1,-4)

Explanation:

This is equation of a Parabola , the general form of which is #ax^2+bx+c# . So here # a=2 ; b=-4 ; c=-2# Let the Co-ordinate of Vertex be # x_1,y_1# . Now we know #x_1 = -b/(2*a)#
#:.# #x_1 = 4/4 =1 # Now plugging in #x_1# in the equation we get #y_1=2*1-4*1-2# or #y_1 = -4# So The Co-Ordinate of Vertex
is (1,-4) [Answer]

Related questions
See all questions in Vertex Form of a Quadratic Equation
Impact of this question
6996 views around the world
You can reuse this answer
Creative Commons License