How do solve the following linear system?: # x/2 - y/4 = -1 , x/3-2y=2 #?

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Answer 1 · 2016-01-02T15:45:01

#x=-30/11#, #y=-16/11#

By substitution method

#x/2-y/4=-1# ---#(1)#

Multiply equation #(1)# by #2#:

#x-y/2=-2#

#x=y/2-2# ---#(2)#

#x/3-2y=2# ---#(3)#

Substitute equation #(2)# into equation #(3)#

#1/3(y/2-2)-2y=2#

#y/6-2/3-2y=2#

#-11/6y=2/3+2#

#-11/6y=8/3#

#y=-16/11#

Substitute #y=-16/11# into equation #(2)#

#x=-8/11-2#

#x=-30/11#

Thus, #x=-30/11#, #y=-16/11#