What is the derivative of #tan(sin x)#?
1 Answer
Jan 2, 2016
Explanation:
Use the chain rule.
According to the chain rule,
#d/dx(tan(u))=sec^(u)*(du)/dx#
Therefore,
#d/dx(tan(sinx))=sec^2(sinx)*d/dx(sinx)#
#=>sec^2(sinx)cosx#
