What is the general form of the equation of a circle with a center at the (10, 5) and a radius of 11?

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Answer 1 · 2016-01-02T17:44:56

#(x-10)^2+(y-5)^2=121#

The general form of a circle:

#(x-h)^2+(y-k)^2-r^2#

Where:

#(h,k)# is the center
#r# is the radius

Thus, we know that

#h=10,k=5#
#r=11#

So, the equation for the circle is

#(x-10)^2+(y-5)^2=11^2#

Simplified:

#(x-10)^2+(y-5)^2=121#

graph{(x-10)^2+(y-5)^2=121 [-10.95, 40.38, -7.02, 18.63]}