How do you graph #y = -½ x + 3# by plotting points?

1 Answer
Jan 3, 2016

See the explanation.

Explanation:

#y=-1/2x+3# is the slope intercept form of a linear equation.

Determine two points on the line by substituting values for #x# into the equation and solving for #y#. You only need two points for a straight line.

Table of Points
#x=0,# #y=3#
#x=6,# #y=0#

Plot the points and draw a straight line through the points.

graph{y=-1/2x+3 [-10, 10, -5, 5]}