Question

A projectile is shot from the ground at a velocity of `1 m/s` and at an angle of `(5pi)/6`. How long will it take for the projectile to land?

Answer 1

`T=0.10204s`

Explanation:

Data:-
Velocity`=V=1m/s`
Angle`=theta=(5pi)/6`
Time of flight `=T=??`
Sol:-
Time of flight is given by`=(2V_(0y))/g`
where `V_(0y)` is the y-component of velocity and `g` is acceleration due to gravity whose value is (9.8 m/s^2).

Y-component of velocity`=V_(0y)=Vsintheta=1*sin((5pi)/6)=0.5`

`T=(2V_(0y))/g=(2*0.5)/9.8=1/9.8=0.1020s`

`implies T=0.10204s`