How do you find the derivative of the function: #3arccos(x/2)#?
1 Answer
Jan 3, 2016
Explanation:
Use the chain rule:
#d/dx(arccos(u))=-(u')/(sqrt(1-u^2))#
Thus,
#d/dx(3arccos(x/2))=3*(d/dx(x/2))/sqrt(1-(x/2)^2)#
#=(3(1/2))/sqrt((4-x^2)/4)=3/(2sqrt((1/4)(4-x^2)))=3/(2(1/2)sqrt(4-x^2))#
#=3/sqrt(4-x^2)#
