How do you find the derivative of sin(2x+1)?

1 Answer
Jan 4, 2016

Use the chain rule.

Explanation:

Say if the problem y=sin(ax+b)
Then you can find the derivative of this using chain rule.

dy/dx = cos(ax+b)*d/dx(ax+b)
dy/dx = cos(ax+b)(a)
dy/dx = acos(ax+b)

Similarly

y=sin(2x+1)
dy/dx = cos(2x+1)d/dx(2x+1)
dy/dx = cos(2x+1)(2)

dy/dx=2cos(2x+1) Answer