Question

What is the antiderivative of `ln(x+1)`?

Answer 1

Basically you are asking for this

#int ln(x+1)dx=int x'*ln(x+1)dx=x*lnx(x+1)-int x*1/(x+1)dx= x*ln(x+1)-int(x+1-1)/(x+1)dx=x*ln(x+1)-x+ln(x+1)#

So the antiderivative of `ln(x+1)` is

`x*ln(x+1)-x+ln(x+1)+c`

where c is a constant