How do you factor #3p^3 +12p^2 + 4p + 16#?

1 Answer
Jan 5, 2016

#(3p^2+4)(p+1)#

Explanation:

Note that the ratio of the coefficients of the first two terms #(3:12)#
is equal to the ratio of the coefficients of the last two terms #(4:16)#
(name, in reduced terms: #(1:4)# )

So if we extract the common factor from the first two terms and the common factor from the last two terms:
#color(red)(3p^3+12p^2) + color(blue)(4p+16)#

#=color(red)((3p^2))color(green)((p+1))+color(blue)((4))color(green)((p+1))#

then extract the common factor from each of these terms:
#=color(purple)((3p^2+4))color(green)((p+1))#