What is the derivative of #sec^2 2x#?
1 Answer
Jan 5, 2016
Explanation:
Use the chain rule. The first issue is the squared term.
#d/dx(sec^2 2x)=2sec2x*d/dx(sec2x)#
Use chain rule again:
#d/dx(sec^2 2x)=2sec2x*sec2xtan2x*d/dx(2x)#
Since
#d/dx(sec^2 2x)=4sec^2 2xtan2x#