How do you solve the following system: #x + 2y = 9 , 7x+15y=32 #?

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Answer 1 · 2016-01-05T20:35:34

The system is

#x+2y=9# (1)

#7x+15y=32# (2)

Multiply the first equation by #-7# and add to the second you get

#(-7)x-14y+7x+15y=-63+32=>y=-31#

hence #x=9+2*31=72#

The solution is #(x,y)#=#(72,-31)#