Question

How would you find the equation of the circle, Center (1,0) Radius =3?

Answer 1

`(x - 1 )^2 + y^2 = 9`

Explanation:

the standard form of the equation of a circle is :

`(x - a )^2 + (y - b)^2 = r^2`

where (a , b ) is the centre and r = radius.

in this case (a , b ) = (1 , 0 ) and r=3

`rArr (x - 1 )^2 + (y - 0 )^2 = 3^2`

`rArr (x - 1 )^2 + y^2 = 9`