What is the slope of #f(x)=-e^x+2x# at #x=1#?
1 Answer
Jan 6, 2016
Explanation:
Find
To find
Since the derivative of
#f'(x)=-e^x+2#
To find the slope (of the tangent line) at that point, plug in
#f(1)=-e^1+2=2-eapprox-0.7183#