How do you factor the expression #9x^2-25#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Meave60 Jan 6, 2016 #(3x)^2-(5)^2=(3x+5)(3x-5)# Explanation: #9x^2-25# fits the form #a^2-b^2#, where #a=3x# and #b=5#. Rewrite the expression as #(3x)^2-(5)^2#. Use the difference of squares: #a^2-b^2=(a+b)(a-b)#. #(3x)^2-(5)^2=(3x+5)(3x-5)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1105 views around the world You can reuse this answer Creative Commons License