Question

An object with a mass of `5 kg` is revolving around a point at a distance of `3 m`. If the object is making revolutions at a frequency of `8 Hz`, what is the centripetal force acting on the object?

Answer 1

I found: `37,850.8N`

Explanation:

Centripetal force is:
`F_c=mv^2/r`
The time taken to complete a complete turn is the period or:
`T=1/("frequency")=1/8s`
The veoocity will be the circumference divided by the period or:
`v=(2pir)/T=(2*3.14*3)/(1/8)=150.7m/s`
So:
`F_c=5*(150.7)^2/3=37,850.8N`