What is the standard form of #y= x(3x-3)(x+2)#?

Question

1482 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-07T08:33:09

The standard form is #y = 3x^3 +3x^2+6x#

We can multiply/expand the expression to get the standard form like this

#y = x( 3x-3)(x+2)#

Step 1: Multiply the last two factor, and combine like terms

#y = x(3x^2 +6x -3x -6)#

#y= x(3x^3 +3x-6)#

Step 2: Distribute the "x" to get

#y = 3x^3 +3x^2+6x#