How do you solve $0.1 d - 0.03 + 0.3 d = 0.25$ $0.1d-0.03+0.3d=0.25$ ?

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Answer 1 · 2016-01-07T10:37:04

$d = \frac{7}{10} = 0.7$ $d=7/10=0.7$

Yuo can thinking that:

$d = x$ $d=x$

then to find d you have to solve the equation

$0.1 x - 0.03 + 0.3 x = 0.25$ $0.1x-0.03+0.3x=0.25$

Addiction the terms in x and move the not x terms on the right of =

$0.4 x = 0.25 + 0.03$ $0.4x=0.25+0.03$

$0.4 x = 0.28$ $0.4x=0.28$

Converting the decimal number in fractions

$\frac{4}{10} x = \frac{28}{100}$ $4/10x=28/100$

Finding the

$m . c . d . = 100$ $m.c.d. =100$

$\frac{10 \cdot 4 x}{100} = \frac{28}{100}$ $(10*4x)/100=28/100$

$\frac{40 x}{100} = \frac{28}{100}$ $(40x)/100=28/100$

$40 x = 28$ $40x=28$

$x = \frac{28}{40}$ $x=28/40$

Semplyfing fraction by 4

$x=cancel(28)^7/cancel(40)_10=7/10$

Then:

$x=d=7/10$

How do you solve 0.1d-0.03+0.3d=0.250.1d−0.03+0.3d=0.250.1d-0.03+0.3d=0.25?