Question

How do you write `7/ x^-2` with positive exponents?

Answer 1

You should get `7x^2`

Explanation:

You need to change "floor" and send `x` from the ground to the first changing the sign of the exponent from `-` to `+`; so:
`7/x^(-2)=7x^(color(red)(+2))`

Answer 2

`7*x^2`

Explanation:

The Exponent properties tell us that:

`a^-n=1/(a^n)`

then:

`7/(x^-2)=7/(1/x^2)=`

with `x!=0`

`=(x^2*7)/(cancel(x^2)*(1/cancel(x^2)))=7x^2`