How do you solve log_x 6 = 0.5logx6=0.5?

1 Answer
Jan 8, 2016

You solve any simple log equation by putting the equation back into exponential form.

Explanation:

Essentially this question is asking you base xx to exponent 1/212 is 6.

log_x6=0.5logx6=0.5
To put this into exponential form, write it like x^0.5=6x0.5=6.
Which is sqrtx=6x=6
The inverse operation of square root is x^2x2, so simply square both sides to get your answer.

(sqrtx)^2=6^2(x)2=62
x=36x=36