Question

What is the vertex of `y= -7(2x-1)^2-3`?

Answer 1

The vertex is `(1/2,-3)`

Explanation:

The vertex form of quadratic function is

`y=a(x-h)^2+k`

Where `(h,k)` is the vertex.

Our problem is
`y=-7(2x-1)^2-3`

Let us try to convert this to the form `y=a(x-h)^2+k`

`y=-7(2(x-1/2))^2 -3`

`y=-7(2^2)(x-1/2)^2-3`

`y=-7(4)(x-1/2)^2 - 3`

`y=-28(x-1/2)^2 - 3`

Now comparing with `y=a(x-h)^2 +k`

We can see `h=1/2` and `k=-3`

The vertex is `(1/2,-3)`

Answer 2

`Vertex (1/2, -3)`

Explanation:

This is actually the vertex form of y.
x-coordinate of vertex:
(2x - 1) = 0 --> `x = 1/2`
y-coordinate of vertex: y = -3