How do you simplify abs(-12 + 22.5i)?

1 Answer
Jan 10, 2016

Please go through the steps given below.

Explanation:

If z=a+ib is a complex number then |z| = sqrt(a^2+b^2)

Our problem is |-12+22.5i|

The modulus is found by the rule mentioned above

|-12+22.5i| = sqrt((-12)^2+(22.5)^2)

|-12+22.5i| = sqrt(144+506.25)

|-12+22.5i| = sqrt(650.25)

|-12+22.5i| = 25.5