How do you solve #-x/3-5=2x#?

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Answer 1 · 2016-01-10T12:50:41

#x=-15/7#

#-x/3-5=2x#

Multiply both sides by #color (red)3#.

#implies color(red)3(-x/3-5)=color(reD)3(2x)#

#implies-x-15=6x#

Add #color (purple) x# on both sides.

#implies color(purple)x-x-15=6x+color(purplE)x#

#implies -15=7x#
#implies 7x=-15#

Divide both sides by #color (blue)7#.

#implies (7x)/color (blue)7=-15/color(blue)7#

#implies x=-15/7#