What is the zeros of the function #h(x) = (4-9x^2)/(2x-5)#?

1 Answer
Topscooter
Jan 11, 2016

#x = +- 2/3#

Explanation:

A fraction is zero if and only if its numerator is zero.

Thus, #h(x) = 0 iff -9x^2 + 4 = 0 iff 9x^2 = 4 iff x^2 = 4/9 iff x = +- 2/3#.

We can keep both solutions because none of them is a zero of the denominator.

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