How do you factor 125a^3-c^3? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Lucio Falabella Jan 11, 2016 125a^3-c^3=(5a-c)*(25a^2+5ac+c^2) Explanation: 125a^3-c^3=5^3a^3-c^3=(5a)^3-c^3 Using the difference of two cubes rule: (b^3-d^3)=(b-d)(b^2+bd+d^2) with: b=5a d=c 125a^3-c^3=(5a-c)(5^2a^2+5ac+c^2)= =(5a-c)*(25a^2+5ac+c^2) Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor x^3 -8? What are the factors of x^3y^6 – 64? How do you know if x^2 + 10x + 25 is a perfect square? How do you write 16x^2 – 48x + 36 as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor 16x^2-36 using the difference of squares? How do you factor 2x^4y^2-32? How do you factor x^2 - 27? See all questions in Factor Polynomials Using Special Products Impact of this question 1708 views around the world You can reuse this answer Creative Commons License