How do you solve #16y+12=9y+33#?

1 Answer
Jim G.
Jan 12, 2016

y = 3

Explanation:

to solve equations of this type it is usual to collect terms with the variable to one side of the equation ( normally left hand side ) and numbers to the other side.

so 16y + 12 = 9y + 33 becomes:

16y - 9y = 33 - 12

hence 7y = 21 and y = 3

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