Question

How do you solve for x in `log10^(x^2)=4`?

Answer 1

`log(x)` and `10^x` are inverse functions, hence `x^2=4` so `x=+-2`.

Explanation:

As Real valued functions, `log(x)` and `10^x` are inverses of one another.

So:

`4 = log(10^(x^2)) = x^2`

Hence `x = +-2`