What is the standard form of #y=(2x-1)(3x+4) #?

1 Answer
mason m
Jan 13, 2016

#y=6x^2+5x-4#

Explanation:

Distribute this using the FOIL method.

#y=(2x-1)(3x+4)=overbrace(2x*3x)^"First"+overbrace(2x*4)^"Outside"+overbrace(-1*3x)^"Inside"+overbrace(-1*4)^"Last"#

#=6x^2+8x-3x-4#

Combine like terms.

#=6x^2+5x-4#

This is in standard form since the exponents are in descending order.

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