Question

How do you solve the following system: #4x-5y= -1, 4x+3y= -1 #?

Answer 1

I found:
`x=-1/4`
`y=0`

Explanation:

I would try multiplying the first equation by `-1` and then add (in columns) to the second to get:
`{(color(red)(-4x-5y=1)),(4x+3x=-1):}` add them
`0-2y=0`
So:
`y=0`
Substitute this back into the first equation:
`4x-0=-1`
`x=-1/4`