How do you condense ln2+2ln3−ln18?
1 Answer
Jan 15, 2016
0
Explanation:
Using the 'laws of logarithms ' :
• logx + logy = logxy
• logx - logy =
log(xy) •
logxn=nlogx Applying these to this question :
ln2+2ln3−ln18=ln2+ln32−ln18=ln2+ln9−ln18
=ln(2×918)=ln(1818)=ln1=0