What is the mass in 3.01 * 10^23 molecules of F_2?

1 Answer
Jan 16, 2016

The answer to this is 1.14 * 10^25 grams

Explanation:

To convert mol F_2 to grams F_2, you simply have to multiply the given number of mol to the molar mass of the compound.

For this case:

g F_2 = (3.01 * 10^(23) mol) * (37.996 g/[mol] )

g F_2 = 1.1436796 * 10^(23)

Using correct number of significant figures,
g F_2 = 1.14 * 10^25 grams

note:
molar mass of F_2 means you have to multiply Fluorine's molar mass by 2.

molar mass of F_2 = 2 * ( 18.992 g/[mol]) = 37.996 g/[mol]