Question

What is the integral of `int tan^2(3x)dx`?

Answer 1

`int tan^2(3x) dx = 1/3 tan(3x) - x + C`

where `C` is the constant of integration

Explanation:

You should know the identity `tan^2theta-=sec^2theta-1`.

`int tan^2(3x) dx = int (sec^2(3x)-1) dx`

`= 1/3 tan(3x) - x + C`

where `C` is the constant of integration.