How do you solve #3x^2 = -12x - 15#?
1 Answer
Jan 17, 2016
Explanation:
Move the terms to the same side of the equation.
#3x^2+12x+15=0#
Divide both sides by
#x^2+4x+5=0#
#x=(-4+-sqrt(4^2-4(1)(5)))/2#
#x=(-4+-sqrt(-4))/2#
As you can now see, this equation only has complex (imaginary) roots.
#x=(-4+-2i)/2#
#x=-2+-i#
