Question

What is the norm of `< -3, -1 , 8 >`?

Answer 1

`sqrt74`

Explanation:

For any vector `A=(a_1,a_2,....,a_n)` in any finite n-dimensional vector space, the norm is defined as follows :

`||A||=sqrt(a_1^2+a_2^2+....+a_n^2)`.

So in this particular case we work in `RR^3` and get :

`||((-3,-1,8))||=sqrt(3^2+1^2+8^2)=sqrt74`.